6) When the pendulum is in motion, when is the tension of the string equal to zero?
(a) When the pendulum is at the turning points on either side of equilibrium
(b) When the pendulum is at the equilibrium position
(c) Somewhere between the turning points and the equilibrium point
(d) The tension in the string is never zero
(e) The tension in the string is always zero
7. The force of gravity acting on the pendulum increases as mass increases, but the period remains the same. How would you explain to someone (without using equations) why that is?1 AnswerPhysics3 days ago
25.00 mL of 1.000 M NaOH solution is mixed with 50.00 mL of 1.000 M HCl solution, both at 21.0 °C. Assuming that the density of both of the solutions is 1.00 g/mL, and that the specific heat capacity is 4.18 JK-1g-1, what is the final temperature of the solution? The heat of neutralization of HCl by NaOH is -63.2 kJ/mol.
NO STEPS REQUIRED
the altitude of a triangle is increasing at a rate of 2.000 centimeters/minute while the area of the triangle is increasing at a rate of 5.000 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 8.000 centimeters and the area is 93.000 square centimeters?
Note: The "altitude" is the "height" of the triangle in the formula "Area=(1/2)*base*height". Draw yourself a general "representative" triangle and label the base one variable and the altitude (height) another variable. Note that to solve this problem you don't need to know how big nor what shape the triangle really is.
any help is appreciated1 AnswerMathematics4 months ago
Gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. It forms a pile in the shape of a right circular cone whose base diameter and height are always the same.
How fast is the height of the pile increasing when the pile is 15 feet high?
Recall that the volume of a right circular cone with height h and radius of the base r is given by V=13πr^2 h.
any help is appreciated2 AnswersMathematics4 months ago
At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 15 knots and ship B is sailing north at 20 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
Note: Draw yourself a diagram which shows where the ships are at noon and where they are "some time" later on. You will need to use geometry to work out a formula which tells you how far apart the ships are at time t, and you will need to use "distance = velocity * time" to work out how far the ships have travelled after time t.
any help with this would be great1 AnswerMathematics4 months ago