Can someone please help me with this ??...plzzz..?
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A hollow square - shaped tube open at both ends is made of iron. The internal square is of 5cm side and the length of the tube is 8 cm. There are 192 cm^3 of iron in this tube.Find ...show more
Other Answers (4)Rated Highest
Volume = area of cross section * length
192 = (x^2 - 5^2) 8
24 = x^2 - 25
x^2 = 49
x = 7 cm
x-5 = 2
This length is twice the thickness.
2/2 = 1 cm
total volume of shape=192 cm^3 = cross section surface x Length
Length = 8 cm
cross section surface = total area - inner area (hollow part)
inner area side = 5 cm
total area side = x
cross section surface = x^2 - (5x5)
192 = (x^2 - (5x5)) x 8
x^2 = 192/8 +5x5
x= 7 cm
t = (7-5)/2
You multiply five with five and then add 192 then subtract with the answer of 5X5+(192divided by8) YOU WILL get some thing and find our the percentage of the same You will get something That is NOT the answer.
Let x be the length of the external square.
(x^2 - 5^2) * 8 = 192