Can someone please help me with this ??...plzzz..?

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A hollow square - shaped tube open at both ends is made of iron. The internal square is of 5cm side and the length of the tube is 8 cm. There are 192 cm^3 of iron in this tube.Find ...show more
Best Answer
Cross-sectional area of iron tube = 192 cm³ / 8 cm = 24 cm²
A = s² - 5² = 24 cm²
s² = 25 + 24 = 49 cm²
s = √(49 cm²) = 7 cm
thickness = ½(7 - 5) = 1 cm
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  • Pradeev answered 5 years ago
    Volume = area of cross section * length
    192 = (x^2 - 5^2) 8
    24 = x^2 - 25
    x^2 = 49
    x = 7 cm
    x-5 = 2
    This length is twice the thickness.
    2/2 = 1 cm
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  • vatchen answered 5 years ago
    total volume of shape=192 cm^3 = cross section surface x Length
    Length = 8 cm
    cross section surface = total area - inner area (hollow part)
    inner area side = 5 cm
    total area side = x
    cross section surface = x^2 - (5x5)

    192 = (x^2 - (5x5)) x 8
    x^2 = 192/8 +5x5

    x= 7 cm

    thickness t
    t = (7-5)/2
    t=1 cm

    Source(s):

    basic calculus
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  • askandasamy answered 5 years ago
    You multiply five with five and then add 192 then subtract with the answer of 5X5+(192divided by8) YOU WILL get some thing and find our the percentage of the same You will get something That is NOT the answer.
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  • dcno02 answered 5 years ago
    Let x be the length of the external square.

    (x^2 - 5^2) * 8 = 192
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