what is the probability of getting a total of 7 at least once in 3 tosses of a pair of fair dice?

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  • Thomas
    Lv 7
    5 years ago

    Subtract the possibility of not getting a 7 at all from 1

    The probability of getting a 7 is (6/6)(1/6)=1/6

    Because the first die can have any value and the second can only be one value that creates the sum of 7

    So the probability of not getting a sum of seven on a given roll is 5/6

    And the probability of not getting a seven three times in a row is

    (5/6)^3=125/216

    And finally the probability of getting at least one 7 is:

    (216/216)-(125/216)=91/216 (42.13%)

    • Asu5 years agoReport

      Thank you 😊

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  • 5 years ago

    over 9000!!!

    • Asu5 years agoReport

      probability cannot exceed 1.

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