# what is the probability of getting a total of 7 at least once in 3 tosses of a pair of fair dice?

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- ThomasLv 75 years ago
Subtract the possibility of not getting a 7 at all from 1

The probability of getting a 7 is (6/6)(1/6)=1/6

Because the first die can have any value and the second can only be one value that creates the sum of 7

So the probability of not getting a sum of seven on a given roll is 5/6

And the probability of not getting a seven three times in a row is

(5/6)^3=125/216

And finally the probability of getting at least one 7 is:

(216/216)-(125/216)=91/216 (42.13%)

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