# Geometry help....?

### 2 Answers

Relevance

- IndicaLv 79 months agoFavorite Answer
∠BPA=∠C, ∠BAP=π/2−B hence ∠ABP=π/2+B−C

Sine Rule to ΔABP : 4/sin(π/2+B−C) = 2R = 4√2 ⟹ cos(B−C) = 1/√2 ⟹ sec(B−C) = √2

- KrishnamurthyLv 79 months ago
Let altitude AD of acute angled triangle ABC be produced

which meets its circumcircle at P such that AP = 4.

If circumradius of triangle is 2 root w then find the value of sec (B - C)

Source(s): https://imgur.com/a/oVIvxT0- Log in to reply to the answers

Still have questions? Get answers by asking now.

Thank you sooo much sir again and again! :))