Anonymous
Anonymous asked in Computers & InternetProgramming & Design · 1 month ago

math problem?

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  • 1 month ago

    First step is to find S6.

    We do that by computing S1 through S5.

    We have S1 = S0. So S1 = {0}

    Then S2 = S1 U S2 = {0} U {0} = {0}

    Knowing S1 and S2 it is analogous that any Sn = {0}

    Therefore S6 = {0}

    Now what is a power set?

    The power set is the set of all subsets of S, including the empty set and S itself.

    Let's take an example.

    For S = {1, 2}

    The power set of S is P(S) = { {}, {1}, {2}, {1, 2} }

    So, in layman's terms, it's all the different combinations you can create with the elements of S.

    Knowing this, the power set of S6 is:

    P(S6) = { {}, {0} }

    So, depending if you want to count the set of outer brackets, the number of opening braces is either 2 or 3

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