Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

# Find the values of a and b such that x^2-4x+9=(x+a)^2+b?

Find the values of a and b such that x^2-4x+9=(x+a)^2+b

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• Anonymous
4 weeks ago

Solutions are infinite !!!

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• If a = -2 and b = 5,

x^2 - 4x  + 9 is a perfect square.

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• If a = -2 and b = 5,

x^2 - 4x  + 9 is a perfect square.

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• x²  - 4x  + 9   = x²  + 2a x + (a²  + b)

2a   = - 4

a   = - 2

b  + 4   = 9

b   = 5

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• x^2-4x+9

=(x^2 - 4x) + 9

=( x^2 - 4x+4) + 9 - 4

=(x - 2)^2 + 5

a = - 2 and b = 5 .. answer//

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• The values of a and b such that

x^2 - 4x + 9 = (x + a)^2 + bx^2 - 4x + 4 + 5 = (x - 2)^2 + 5

a = -2 and b = 5

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• a=-2 b=5...............

• rotchm
Lv 7
1 month agoReport

Flagged for point harvesting and for giving out explicit answers.

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• Anonymous
1 month ago

a = -2

b = 5

Plug them in.

• rotchm
Lv 7
1 month agoReport

Flagged for point harvesting and for giving out explicit answers.

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• complete the square

x^2 - 4x + 9 =

x^2 - 4x + 4 + 5 =

(x - 2)^2 + 5

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• Expanding (x+a)^2+b gives you ?

In there, whats the coefficient of x?

Answer these & we will proceed.

Hopefully no one will spoil you the answer thereby depriving you from your personal enhancement; that would be very inconsiderate of them.   Too late  :(

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