What volume (in L) will 5.5 g of oxygen gas occupy if 2.2 g of the oxygen gas occupies 3.0 L? (Under constant pressure and temperature.)?

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  • Anonymous
    1 month ago

    Simple ratio.

    3L / 2.2 g = X / 5.5 g 

    Solve for X

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  • Dr W
    Lv 7
    1 month ago

    from the ideal gas law

    .. P1V1 / (n1T1) = P2V2 / (n2T2)

    if P and T are constant

    .. V1/n1 = V2/n2

    rearranging

    .. V2 = V1 * (n2 / n1)

    since n = mass / mw 

    .. V2 = V1 * (mass2 / m2) / (mass1 / mw)

    since mw = 32 g/mol and is a constant

    .. V2 = V1 * mass2 / mass1

    solving

    .. V2 = 3.0L * (5.5g / 2.2g) = 7.5L

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  • 1 month ago

    Volume of 5.5 g O2 = 5.5g / 2.2 g * 3.0 L = 7.5 L

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  • 1 month ago

    (3.0 L)*(55/22) = 7.5 L.

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  • 1 month ago

    The formal relationship is Avogadro's law stated as:

    V1/n1 = V2/n2

    But moles of a gas in a sample is directly proportional to mass of the sample, so substituting masses for moles works:

    V1/mass1 = V2/mass2

    3.0 / 2.2 = V2 / 5.5

    V2 = 7.5 L

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  • 1 month ago

    5.5g (3.0L/2.2g) = 7.5L

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