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# the potential difference across two plates is 1.50 V. If the plates are 8.22*10^-4 m apart, what is the electric field between them?

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- Anonymous1 month agoFavorite Answer
The field can be expressed in V/m (or N/C), so one might reasonably guess that

field = potential / distance

here

E = 1.50V / 8.22*10^-4m = 1.82*10*3 V/m (or N/C)

1820 N/C

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- MyRankLv 61 month ago
Given,

Potential difference (v) = 1.50 volts

Distance (d) = 8.22 x 10⁻⁴m

Electric field (E) =?

We know that:-

Electric field (E) = v/d = 1.50 volts / 8.22 x 10⁻⁴m = 1.82 x 10³v/m

∴ Electric field (E) = 1.82 x 10³v/m.

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