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# A hot air balloon has just lifted off and is rising at the constant rate of 1.8 m/s. Suddenly, one of the passengers realizes she has left..?

...her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 11.2 m/s. If the passenger is 2.5m above her friend when the camera is tossed, how high is she when the camera reaches her?

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- NCSLv 71 month ago
We can't find her height directly. But after some time t, the camera and passenger will have the same height:

h = 2.5m + 1.8m/s*t - ½gt² = 11.2m/s*t - ½gt²

dropping units for ease (t is in seconds)

2.5 + 1.8t = 11.2t

2.5 = 9.4t

t = 0.266 s

passenger height

h = 2.5m + 1.8m/s*0.266s - ½*9.8m/s²*(0.266s)² = 2.6 m

check:

camera height

h = 11.2m/s*0.266s - ½*9.8m/s²*(0.266s)² = 2.6 m

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okay done