How many grams of hydrated MgSO 4 ⋅ 5 H 20 (M.W.: MgSO 4 = 119, H 20 = 18) are required to make a 10% solution of MgS0 4?

Please help this utterly lost chemistry student!

2 Answers

  • Anonymous
    1 month ago

    As Roger said, you don't have enough information.  Let's assume they want 1 L of 10% m/v solution.

    10% m/v of 1 L = 100 g of MgSO4 (you don't leave a space between the O and the 4).

    Since the MgSO4 exists as MgSO4-5H2O, you need 100 g * ((119 + 5 * 18)/119 g) = mass of the hydrate.

    Of course, if you want 100 mL of 0.1 M, the answer is going to be totally different.

    • BadWolf1 month agoReport

      Thanks! I feel as if all the questions given to me by the professor are missing a lot of important information... Makes me feel a bit better knowing that I'm not the only one lost by this question.

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  • 1 month ago

    It depends on:

    1) How much solution do you need?

    2) What kind of percent are we talking about here? mass? moles?

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