The force on a 0.66 m wire that is perpendicular to Earth's magnetic field is 0.18 N. What is the current in the wire? Use 5.0 ✕ 10-5 T for Earth's magnetic field.
- FiremanLv 72 months agoFavourite answer
BY F = iLBsinθ
=>0.18 = i x 0.66 x 5 x 10^-5 x sin90*
=>i = 5.45 x 10^3 amp
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