Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

Transmittance question?

I'm trying to rework the equation of absorbance below (it is the negative logarithm of the transmittance) so I can find the transmitted light intensity (I) but I don't really understand how to do so. Any help would be great, thanks!

A = -log I/Io

A =  0.5

I = transmitted light intensity (trying to find)

Io = 200

2 Answers

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  • ?
    Lv 7
    2 months ago
    Favourite answer

    Given

    .....A = -log I/Io

    .....A =  0.5

    .....I = transmitted light intensity (trying to find)

    .....Io = 200

    0.5 = -log I/200

    log I/200 = -0.5

    10⁻⁰·⁵ = I/200

    0.31623 = I/200

    I = (0.31623)(200)

    I = 63.246.....................ANS

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  • 2 months ago

    As A = - log (I/Io)

    =>(10)^-A = (I/Io)

    =>10^A = Io/I

    =>10^0.5 = 200/I

    =>3.16 = 200/I

    =>I = 200/3.16

    =>I = 63.25

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