# How to deduct centripetal force from the linear regression slope of a Radius vs Period^2 graph?

I have a graph representing Radius / T(period)squared, and a linear regression equation for the trendline. Question is what does the slope of the linear equation represent? How do i deduct the centripetal force from it?

### 1 Answer

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- 5 months ago
Centripetal Force = 4pi^(2)mr / T^2

What you have is r / T^2. Let that be 'a'

'a' represents how fast radius changes with respect to changing period^2

To deduct Centripetal Force: Fc = 4pi^(2)ma

I actually have no idea if I'm right

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