# In the square QRST, QR= 4. Find the shaded area if Q,R,S,T are the centers of the area that constitute the figure.?

Options are;

A.16-6pie

B.16-4pie

C.6-8pie

D.16-2pie

Please give complete solution to this question.

### 10 Answers

- PhilomelLv 74 weeks agoFavourite answer
The area of the square = 4*4=16.

The 1/4 circles make up a circle of r=2

area of the circle =pi*R^2=4pi

shaded area =16-4pi

- la consoleLv 74 weeks ago
shaded_area = square - disk

shaded_area = (4 * 4) - (π.r²) → where r is the radius of the disk (red - yelow - green - cyan)

shaded_area = 16 - π.r² → where: r = (QR/2) = 4/2 = 2

shaded_area = 16 - 4π ← b) answer

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- PuzzlingLv 74 weeks ago
If you shift the four corners around, you can see this is equivalent to taking the area of the square (sides = 4) and subtracting a circle (radius = 2).

4² - π(2²)

= 16 - 4π

Answer:

B. 16 - 4π

P.S. Please don't misspell the Greek letter π (pi) with an ending 'e'. One is a mathematical constant and the other is a baked dish with pastry and a filling.

π = pi

🥧 = pie

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- Engr. RonaldLv 74 weeks ago
solving its radius

given QR = 4

r = QR/2 = 4/2 = 2

solving the quarter area of a circle.

A = 1/4πr^2A = 1/4π(2)^2 = π

Area of square

A = S^2 = 4^2 = 16

Total Area of 4 quarter circle = 4A = 4π

solving the area of a shaded region.

A =Area of square - total Area of 4 quarter circle

A = 16 - 4π Answer//

Answer is B 16 - 4pie

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- PinkgreenLv 74 weeks ago
The shaded area=4^2-4[pi(2^2)/4]=16-4pi.

Ans. B

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- PhilipLv 64 weeks ago
Let TS be the x-axis with T at the origin (0,0). Let TQ be the y-axis with Q at (0,4).

Then r is at (4,4) and S is at (4,0). The sum of all non-shaded areas is a circle with

radius = 2 whose area = pi(2^2) = 4pi. The square's area = 4^2. The shaded area = square's area - circle's area = 16-4pi. Option B. shows the correct answer.

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- AshLv 74 weeks ago
Area of shaded area = Area of square - Area of 4x quarter circles

= (4*4) - 4*¼(π2²)

= 16 - 4π

Answer B

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- KrishnamurthyLv 74 weeks ago
In the square QRST, QR = 4.

Find the shaded area if Q, R, S, and T are

the centers of the area that constitute the figure.

The answer option is B.

Options given are

A. 16 - 6π, B. 16 - 4π, C. 16 - 8π, and D. 16 - 2π

How

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Nice