Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

Find the area of the following figure?

Attachment image

12 Answers

Relevance
  • 1 month ago

    The diagram is a trapezium

    Area of a trapezium is  = Average Length of two sides multiplied by height

    = 4*(10+6)/2=32

  • 1 month ago

    A = 1/2h(a + b)

    A = 1/2(4)(10 + 6)

    A = 32 cm^2 Answer..//

  • 1 month ago

    If you move the left hand triangle to the other end you end up with a rectangle 8 x 4 cm.

    4*8= 32 cm^2

  • 1 month ago

    Area=(6+10)*4/2=32 cm^2

  • What do you think of the answers? You can sign in to give your opinion on the answer.
  • Pope
    Lv 7
    1 month ago

    There is insufficient given information to derive the area. The image suggests a trapezoid, and that was the assumption in at least five responses preceding mine, but that is not actually a given condition. We are given no reason to conclude that any two sides are parallel.

  • sepia
    Lv 7
    1 month ago

    A = (6 + 24 + 2) cm^2 = 32 cm^2

  • 1 month ago

    The area of the given figure is 32 cm^2.

  • 1 month ago

    Assuming it is a symmetric trapezium, then 

    A = h(L + S) / 2

    Where 

    A = area 

    h = perpendicular height ( 4cm) 

    L = longer parallel side (10 cm) 

    S = shorter parallel side (6 cm) 

    Substitute 

    A = 4(10 + 6) / 2 

    A = 2(10 + 6)

    A = 2(16) 

    A = 32 cm^2 

  • 1 month ago

    The equation for the area of a trapezoid is:

    A = (b₁ + b₂)h / 2

    We have values for all three unknowns.  Substitute and simplify:

    A = (10 + 6)(4) / 2

    A = 16(4) / 2

    A = 64 / 2

    A = 32 cm²

  • Robert
    Lv 7
    1 month ago

    It would have been easier to

    google "trapezoid area"

Still have questions? Get answers by asking now.