The length of a  rectangle  is twice its width. If the  perimeter  of the rectangle is  30 cm,  find its  area .?

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  • Vivian
    Lv 4
    3 weeks ago

    Abbreviations: Length = L, Perimeter = P, Width = W, Area = A

    Area = Length:Width = L:W = 2:1

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  • RR
    Lv 7
    4 weeks ago

    L:W = 2:1

    2 + 1 = 3 parts

    30/3 = 10 = 1 part

    10 x 2 = 20 = 2 parts

    However, this is 2L and 2W

    therefore L = 20/2 = 10

    and W = 10/2 = 5

    Arera = L x W

    = 10 x 5

    = 50 sq cm

  • 4 weeks ago

    L = 2W

    P = 30 = 2(L+W) = 2(3*W) = 6W

    So W = 5 cm and L = 10 cm

    A = L*W = 10*5 = 50 cm^2

  • 1 month ago

    Here is a handy graphic I put together to help you get your answer, https://i.postimg.cc/mZ54cg9n/Screenshot-2020-07-1...

    Source(s): I've taught math plus many other subjects. And have helped out lots of students to help them better understand and learn.
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  • 1 month ago

    50 sq cm is its  area

  • 1 month ago

    The length of a rectangle is twice its width. 

    If the perimeter of the rectangle is 30 cm, 

    its area is 50 cm^2.

  • David
    Lv 7
    1 month ago

    Area of rectangle: 10 times 5 = 50 square cm

  • 1 month ago

    l = 2w

    p = 2l + 2w

    30 = 2l + 2w

    Substitute for l = 2w

    30 = 2(2w) + 2w

    30 = 4w + 2w

    30 = 6w

    Divide both sides by 6

    5 = w

    w = 5 cm

    Remember 

    l = 2w

    l = 2(5)

    l = 10 cm

    ---------------

    Area

    a = l * w

    a = 10 * 5

    a = 50 cm² <––––––

  • 1 month ago

    it is 5 x 10 ... you do the rest.  ps -- on the exam you'll have to show how you proved that

  • BJJ
    Lv 7
    1 month ago

    The length is 10 cm and the width is 5 cm 

    The area is 5 cm x 10 cm = 50 cm 

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