Anonymous
Anonymous asked in Education & ReferenceHomework Help · 2 months ago

How to do this problem?

A Campbell’s Soup can is 15cm tall and has a radius of 5 cm. 

How much paper is needed to make the label (think about what the label covers)?

How much soup can this can hold? (1 cm3 = 1 mL)

4 Answers

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  • 2 months ago
    Favourite answer

    How much paper is needed to make the label (think about what the label covers)?

    a = circumference * height

    a = 2πr * h

    a = 2π(5) * 15

    a = 471.2cm²  <––––––

    ------------------------

    How much soup can this can hold?

    v = area * height

    v = πr² * h

    v = π(5²) * 15

    v = π(25) * 15

    v = 1,178cm³ 

    v =  1,178 mL

    v = 1.178 L <––––––

  • 2 months ago

    get out a soup can and measure up and down, and around, and multiple. {Beats the heck out of learning math formulas.} GO STEM !!

  • RR
    Lv 7
    2 months ago

    15cm x the circumference of the can will give you the surface area of the side of the can:

    C = 2πr

    = 2π x 5

    = 31.42 cm

    31.42 x 15 = 471. 23 cm²

    You would need 471. 23 cm² (with no overlap)

    ____________

    You can work out the volume by working out the area of the top or bottom and multiplying by the height;

    A = πr²

    = π x 5²

    = π x 25

    = 78.54 cm²

    78.54 x 15 = 1178.10 cm cubed = 1178.1 ml = 1.178 Litres

  • ?
    Lv 7
    2 months ago

    The base of the can is a circle of radius 5cm.

    The circumferene of the base circle is 2πr = 10π cm

    The label will be a rectangle with length = 10π cm and width = 15 cm............ANS

    Area of the label would be (10π cm)(15 cm) = 150π cm²............ANS

    The can of soup can hold πr²h = π5²15 = 375π cm³ = 375π mL...................ANS

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