# Math question ?

Train A traveling at 200 mph leaves station at 1 pm. Both stations are directly across from each other and X miles away. If the trains meet at 4 pm what is X?

### 5 Answers

- KrishnamurthyLv 71 month ago
Train A, traveling at 200 mph, leaves station A at 1 pm.

Train B, traveling at 300 mph, leaves station B at 3 pm.

Both stations are directly across from each other and x miles away.

The trains meet at 4 pm.

What is x?

x is (600 + 300) or 900 miles.

- PuzzlingLv 71 month ago
Here's the full question:

Train A, traveling at 200 mph, leaves station A at 1 pm. Train B, traveling at 300 mph, leaves station B at 3 pm. Both stations are directly across from each other and x miles away. The trains meet at 4 pm. What is x?

At 4 pm, train A has been traveling for 3 hours.

3 hours × 200 mph = 600 miles

At that time, train B has been traveling for 1 hour.

1 hour × 300 mph = 300 miles

Answer:

x = 900 (miles)

- micatkieLv 71 month ago
The question states that "If the trains meet .....". This indicates that there are two or more trains.

What is/are the other train(s) ?

- What do you think of the answers? You can sign in to give your opinion on the answer.
- Donnie PorkoLv 71 month ago
Are you missing something.

If train a leaves at 1 pm at 200 mph. At 4 pm, it would have traveled 3 hours. So 200 mph * 3 hr = 600 miles. So x us 600 mikes from train A starting point.