HB asked in Science & MathematicsEngineering · 2 months ago

A small heating coil has a constant resistance of 25 W. a) How much power would the coil consume if the voltage drop across it is 96 V?

7 Answers

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  • Anonymous
    1 month ago

    25 W is not a resistance. 

    You need to learn some electrical terminology before coming here to ask a question.

  • 2 months ago

    resistance is measured in Ohms, 

    Not Watts.If you meant Ohms, IE the coil has 25 Ohms resistancethem power expended in the coil is given by Power = V x Ior V^2 / R= 368.64 Watts 

  • Jim
    Lv 7
    2 months ago

    The "units" are extremely important. Did you mean 'ohms'??

    IF ohms, then:

    I = V/R and Watts = I*V So Watts = V²/R

    W = (96)²/25 = 368.64 w, but I would round to 370 w

  • 2 months ago

    how tall am i, if i am 5'6"

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  • 2 months ago

    The resistance is 25w/96v=.260Ω

    It will use 25W.

    If the coil is 25Ω the the power will be 96^2/25= 387 W.

  • 2 months ago

    AS YOU MARKED ON QUESTION ------->>> 25W  !!!

  • 2 months ago

    a)

    The resistance should "25 Ω" instead of "25 W".

    Power of the coil consumed

    = v²/R

    = 96²/25

    = 370 W (to 2 sig. fig.)

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