# Please! someone help me with this problem If g(x)=4x^2-3x^2+2x-2, find g(2) and g(1/2)?

g(2) my answer is 6 but my online feedback said that answer is wrong after I submit my online quiz and the g(1/2) I got -3/4 and converted to decimal which I got -0.75 and my school mate said according to his online feedback -0.75 was a wrong answer so I decided to convert that into the nearest tenth which is -0.8 but again my online feedback said my answer is wrong.. Maybe I'm going to try -3/4 on my next final attempt, but I'm not so sure myself :( Relevance
• My guess is there is a *typo* in the first term where that is supposed to be *cubed*. There's no reason to have two terms both with x².

If we correct the function, we have:

g(x) = 4x³ - 3x² + 2x - 2

g(2) = 4*2³ - 3*2² + 2*2 - 2

= 32 - 12 + 4 - 2

= 22

g(½) = 4*(½)³ - 3(½)² + 2*(½) - 2

= 4/8 - 3/4 + 1 - 2

= 1/2 - 3/4 - 1

= -5/4 (or -1.25)

Try those answers to confirm whether a typo is the issue.

•  If g(x) = 4x^2 - 3x^2 + 2x - 2,

g(2)  = 6

and

g(1/2) = - 3/4

• g(2) = 4(2)² - 3(2)² + 2(2) - 2

so, 4(4) - 3(4) + 4 - 2

=> 16 - 12 + 4 - 2 = 6....agreed.

g(1/2) = 4(1/2)² - 3(1/2)² + 2(1/2) - 2

so, 4(1/4) - 3(1/4) + 2(1/2) - 2

=> 1 - 3/4 + 1 - 2 = -3/4...agreed.

I would guess that your online system is only accepting fractions rather than decimals.

The main thing is your answers are correct, so I assume you have a similar method of working to mine.

:)>