# What is the change in entropy of 1.00 kg of liquid water at 100°C as it changes to steam at 100°C? Has to be in J/K ?

What is the change in entropy of 1.00 kg of liquid water at 100°C as it changes to steam at 100°C?

### 2 Answers

Relevance

- Dr. ZorroLv 72 months ago
ΔS = ∫︎ dQ / T

Note that during a phase transition T is constant, so 1/T can be taken out in front of the integration. The integral of dQ will add up to the heat of vaporization of 1kg of water, L.

So

ΔS = L / T

L = 2.260kJ/kg * 1.00kg = 2260 J

T = 373 K

ΔS = 2260J / 373K = 6.05 J/K

Still have questions? Get answers by asking now.