6g ethanoic acid act with 6.4 g zinc. What is the mass of the salt created on the right side?

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  • 1 month ago
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    2 HC2H3O2 + Zn → Zn(C2H3O2)2 + H2

    (6 g HC2H3O2) / (60.052 g HC2H3O2/mol) = 0.09991 mol HC2H3O2

    (6.4 g Zn) / (65.380 g Zn/mol) = 0.09789 mol Zn

    0.09991 mole of HC2H3O2 would react completely with 0.09991 x (1/2) =

    0.049955 mol Zn, but there is more Zn present than that, so Zn is in excess and HC2H3O2 is the limiting reactant.

    (0.09991 mol HC2H3O2) x (1 mol Zn(C2H3O2)2 / 2 mol HC2H3O2) x

    (183.468 g Zn(C2H3O2)2 / mol) = 9.2 g HC2H3O2

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