Anonymous
Anonymous asked in Business & FinancePersonal Finance · 1 month ago

Each step in the following process has a yield of 70.0%. CH4+4Cl2⟶CCl4+4HCl CCl4+2HF⟶CCl2F2+2HCl?

Each step in the following process has a yield of 70.0%.

CH4+4Cl2⟶CCl4+4HCl

CCl4+2HF⟶CCl2F2+2HCl

The CCl4 formed in the first step is used as a reactant in the second step.

If 6.50 mol CH4 reacts, what is the total amount of HCl produced? Assume that Cl2 and HF are present in excess.

1 Answer

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  • Anonymous
    1 month ago

    another wrong category DISHONEST CHEATER.

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