I need help with this question if possible.?
- KrishnamurthyLv 71 month ago
A student records the following information:
Mass of empty 150-mL beaker: (6.4750 × 10^1) g
Mass of 150-mL beaker + water: (1.864 × 10^2) g
Initial mass of sodium chloride in 2nd beaker: (1.6 × 10^2) g
Final mass of sodium chloride in 2nd beaker: (9.7940 × 10^1) g
Calculate the mass percent of the sodium chloride solution in % by mass.
Report your answer to three significant figures.
Mass of water = (1.864 × 10^2) g - (6.4750 × 10^1) g = 121.65 g
- billrussell42Lv 71 month ago
beaker = 64.75 g
beaker+water = 186.4 g
initial mass of NaCl + 2nd beaker = 106 g
final mass of NaCl + 2nd beaker = 97.94 g
?? you have, apparently, 2 beakers. You have mass of first, but not mass of second.
Also unknown is what causes the mass of NaCl to change
too much missing data.