Anonymous
Anonymous asked in Science & MathematicsPhysics · 4 weeks ago

A ball rolls off a 6m ledge and lands 4m away from the edge of the ledge. What was the ball's initial velocity?

Any help is appreciated!

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  • NCS
    Lv 7
    4 weeks ago
    Favourite answer

    vertically we can use

    h = ½gt²

    so time to fall t = √(2h/g) = √(2*6m / 9.8m/s²) = 1.1 s

    horizontal velocity was

    v = d / t = 4m / 1.1s = 3.6 m/s

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  • 4 weeks ago

    roughly

    the ball falls at 9.81m per second

    so 6/9.81 = .61 seconds of flight

    the ball must have travelled 4m/.61 seconds is the velocity

    resolve to m/s for the correct unit

    (.61 is not accurate - use the equations of motion to get the accurate number)

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