If a projectile flies north at 423 meters in 6.8 seconds, what is its velocity?

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  • 4 weeks ago

    Unable to determine, due to lack of vector data.

  • 1 month ago

    Without comments it is extremely difficult to add to others statements.  The velocity MUST include a direction.  As NCS has done.  If the projectile lands at this distance then there is no vertical displacement so the velocity over this time has NO vertical component.  It is horizontal, 423/6.8 = 62 m/s North.

  • 1 month ago

    Idk if by north you mean up. If not, it should be irrelevant. If you mean displaced 423 meters horizontally, then its horizontal velocity is 62.2 m/s given the air resistance is negligible. 

    If you’re saying the projectile displaced 423 meters vertically, then its final velocity is 95.5 m/s and it’ll either be in the first or second half of its projectile motion. This is ignoring air resistance.

  • NCS
    Lv 7
    1 month ago

    423m [N] / 6.8s = 62 m/s [N]

    as your velocity has both magnitude and direction.

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  • Ash
    Lv 7
    1 month ago

    velocity = distance/time = 423 m / 6.8 s = 62.2 m/s

  • 1 month ago

    the horizontal component of the velocity is 423/6.8 m/s

    the vertical component and total velocity are unknown.

  • 1 month ago

    423/6.8. Do the math. 

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