k asked in Science & MathematicsChemistry · 4 weeks ago

chem helppppppppppppp fast?

Copper(II) chloride and lead(II) nitrate react

in aqueous solutions by double replacement.

Write the balanced chemical equation, the

overall ionic equation, and the net ionic equation for this reaction. If 11.84 g of copper(II)

chloride react, what is the maximum amount

of precipitate that could be formed?

1 Answer

Relevance
  • 4 weeks ago

    balanced chemical equation:

    CuCl2 + Pb(NO3)2 → Cu(NO3)2 + PbCl2(s)    [balanced as written]

    overall ionic equation:

    Cu{2+} + 2 Cl{-} + Pb{2+} + 2 NO3{-} → Cu{2+} + 2 NO3{-} + PbCl2(s)

    net ionic equation

    2 Cl{-} + Pb{2+} → PbCl2(s)

    (11.84 g CuCl2) / (134.452 g CuCl2/mol) x (1 mol PbCl2 / 1 mol CuCl2) x

    (278.106 g PbCl2/mol) = 24.49 g PbCl2

Still have questions? Get answers by asking now.