Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

# If something is traveling at constant acceleration of +14.9 m/s^2. How long will it take to reach an intercept velocity of +390.7 m/s?

Can some tell me the equation to use for this question?

Relevance
• 2 months ago

390.7/14.9=26.22 Seconds........................

• 2 months ago

The equation IS THE ANSWER.  Actually reducing it to numbers is a waste of time.

• 2 months ago

In 1 second, it gains 14.9 m/s.

In 2 seconds, it gains 2 * 14.9 m/s.

In 3 seconds, it gains 3 * 14.9 m/s.

Do you see a pattern here?

In "x" seconds it gains x * 14.9 m/s. Just solve the equation x * 14.9 = 390.7.

• oubaas
Lv 7
2 months ago

for stretching the same space

397t = 14.9/2*t^2

14.9t = 397*2

t =  2V/a = 397*2 /14.9 = 53.28 sec

for getting the same speed

t' = V/a = t/2 = 26.64 sec

• ?
Lv 7
2 months ago

𝑣 = a*t + 𝑣₀

To achieve 390.7 m/s:

390.7 = 14.9 * t

t = 26.221476510067114093959731543624 s

Now round to 3 sigfigs: 26.2 s