You wish to cool a 1.83 kg block of brass initially at 80.0°C to a temperature of 57.0°C by placing it in a container of water.?
You wish to cool a 1.83 kg block of brass initially at 80.0°C to a temperature of 57.0°C by placing it in a container of water initially at 32.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of water are respectively 1,000 kg/m3 and 4,186 J/(kg · °C), and the specific heat of brass is 380 J/(kg · °C).
- NCSLv 72 months agoFavourite answer
Boiling has nothing to do with it.
heat lost by brass = heat gained by water
1.83kg * 380J/kg·ºC * (80.0-57.0)ºC = M * 4186J/kg·ºC * (57.0-32.0)ºC
M = 0.153 kg
which has volume 0.153 L ◄
since water has density 1kg/L
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