You wish to cool a 1.83 kg block of brass initially at 80.0°C to a temperature of 57.0°C by placing it in a container of water.?

Question

You wish to cool a 1.83 kg block of brass initially at 80.0°C to a temperature of 57.0°C by placing it in a container of water initially at 32.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of water are respectively 1,000 kg/m3 and 4,186 J/(kg · °C), and the specific heat of brass is 380 J/(kg · °C).

Answer 1

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Boiling has nothing to do with it.

heat lost by brass = heat gained by water

1.83kg * 380J/kg·ºC * (80.0-57.0)ºC = M * 4186J/kg·ºC * (57.0-32.0)ºC

solves to

M = 0.153 kg

which has volume 0.153 L ◄

since water has density 1kg/L

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