Here is a physics question I've been stuck on?
A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?
- PhilomelLv 72 months ago
v=500 sin(30)=500*.5= 250m/s .
- MorningfoxLv 72 months ago
The components are V sin(angle) and V cos(angle). I can't automatically remember which is horizontal and which is vertical, so I have to think about it. If the angle was zero, then the components would be 0 vertical, and V horizontal. So then, which one of these is equal to zero: V sin(0) and V cos(0)?