Physics question: Error propagation?
Help! I'm trying to find the error propagation and uncertainty (m ± ∆m) for m where the given formula is
mg = (m1 g sin theta) + (m2 g sin theta)
Note:
m1,m2 = 0.2kg
Theta = 30 degrees
m = unknown value, (though I calculated using the given formula n I got 0.2kg!)
Please help, I'm desperate. I got nothing in my mind, blank
I'm using 9.8 for g
1 Answer
- Anonymous2 months ago
Update.
mg = m₁gsinθ + m₂gsinθ
The first thing to note is g cancels out giving:
m = m₁sinθ + m₂sinθ
So the value of g isn’t used. I should have spotted that in my first answer.
It is *essential* to know the uncertainties for m₁, m₂ and θ. This will depend on how they have been measured. But you give no information. I’ll make up some values for illustration.
There are several different methods and I don’t know which one you are supposed to use. I’ll show you the simplest method.
m₁ = (0.200±0.001) kg
m₂ = (0.200±0.001) kg
θ = (30±2)º
m = m₁sinθ + m₂sinθ
. . = 0.200* ½ + 0.200* ½
. . = 0.200 kg (agreed)
______________________
m₂_min = 0.199 kg
m₁_max = 0201 kg
m₂_min = 0.199 kg
θ_min = 28º
θ_max = 32º
m_min = 0.199sin(28º) + 0.199sin(28º)
. . . . . . .= 0.213kg
m_max = 0.201sin(32º) + 0.201sin(32º)
. . . . . . .= 0.187kg
m = (0.200±0.013) kg