# Calculate the pressure, in atmospheres, of 2.05 moles of helium gas in a 10.0-L container at 29 ∘C.?

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- King LeoLv 72 months ago
PV = nRT

P = nRT/V

Let’s find the right ‘R’ on wikipedia.

https://en.wikipedia.org/wiki/Gas_constant

R ≈ 0.08206 L atm K‾¹ mol‾¹

so temperature will be quoted in Kelvins, T = 29℃ = 302.15K

P = nRT/V

P = ( 2.05 mol )( 0.08206 L atm K‾¹ mol‾¹ )( 302.15K ) / ( 10.0L )

P = 5.08 atm

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