Calculate the pressure, in atmospheres, of 2.05 moles of helium gas in a 10.0-L container at 29 ∘C.?

2 Answers

Relevance
  • 2 months ago

    PV = nRT

    P = nRT/V

    Let’s find the right ‘R’ on wikipedia.

    https://en.wikipedia.org/wiki/Gas_constant

    R ≈ 0.08206 L atm K‾¹ mol‾¹

    so temperature will be quoted in Kelvins, T = 29℃ = 302.15K

    P = nRT/V

    P = ( 2.05 mol )( 0.08206 L atm K‾¹ mol‾¹ )( 302.15K ) / ( 10.0L )

    P = 5.08 atm

    -------------

    Attachment image
  • 2 months ago

    Do your own homework 

Still have questions? Get answers by asking now.