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- az_lenderLv 72 months agoFavourite answer
Let u = x^2 - 2x - 15. Then du = (2x - 2) dx, and

(1/2) du = (x - 1) dx. So now your integrand is

(1/2) e^u du.

I think you know that the integral itself is then (1/2) e^u.

Putting back u = x^2 - 2x - 15, the indefinite integral is

(1/2)e^(x^2 - 2x - 15).

Putting in the limits of integration, you get

(1/2)e^9 - (1/2)e^(-7).

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