Kat asked in Science & MathematicsChemistry · 2 months ago

Suppose 16.84 mL of 0.465 M Ca(OH)2 is required to neutralize 18.4 mL of aqueous HCl solution. What is the molarity of the HCl solution?

Suppose that 16.84 mL of 0.465 M Ca(OH)2

is required to neutralize 18.4 mL of aqueous

HCl solution. What is the molarity of the HCl

solution?

Answer in units of M.

1 Answer

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  • 2 months ago

    Write the chemical equation for the reaction:

    2HCl + Ca(OH)2 ---> CaCl2 + 2H2O

    The 2:1 ratio between HCl and Ca(OH)2 will be used below.

    millimoles Ca(OH)2 ---> (0.465 mmol/mL) (16.84 mL) = 7.8306 mmol

    For every 1 mole of Ca(OH)2 neutralized, 2 moles of HCl are required. Therefore:

    (7.8306 mmol) (2) = 15.6612 mmol of HCl

    molarity HCl ---> 15.6612 mmol / 18.4 mL = 0.8512 M

    Round off more, as you see fit.

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