Calculate the pH of the solute in an aqueous solution of 0.663 M NH3(aq) if the Kb is 1.8 × 10−5 .?

Question

additionally What is the percentage protonation of the

solute?

Answer in units of %

Answer 1

NH3+ H2O = NH4+ + OH- 

[OH-] = SQRT(1.8 × 10−5 * 0.663) = 3.45E-03

pOH = 2.462 pH = 14-pOH = 11.5

% protonation = [NH4+] / [NH3] % = 3.45 *10 ^-3 / 0.663 %  = 0.52 % 

Answer 2

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