Calculate the pH of the solute in an aqueous solution of 0.663 M NH3(aq) if the Kb is 1.8 × 10−5 .?
additionally What is the percentage protonation of the
Answer in units of %
- BobbyLv 72 months ago
NH3+ H2O = NH4+ + OH-
[OH-] = SQRT(1.8 × 10−5 * 0.663) = 3.45E-03
pOH = 2.462 pH = 14-pOH = 11.5
% protonation = [NH4+] / [NH3] % = 3.45 *10 ^-3 / 0.663 % = 0.52 %
- Anonymous2 months ago
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