A mixture of gases contains 0.310 mol CH4, 0.240 mol C2H6, and 0.300 mol C3H8. The total pressure is 1.35 atm. ?
Calculate the partial pressures of the gases.
- az_lenderLv 72 months ago
The partial pressures are proportional to the moles.
Note that the total number of moles is 0.85.
The partial pressures are (0.31/0.85)*(1.35 atm) for CH4,
(0.24/0.85)*(1.35 atm) for C2H6,
and (0.30/0.85)*(1.35 atm) for C3H8.
Use a calculator to finish...