Lili asked in Science & MathematicsPhysics · 2 months ago

In a scene in an action movie, a stuntman jumps from the top of one building to the top of another building....?

 In a scene in an action movie, a stuntman jumps from the top of one building to the top of another building. After a running start, he leaps at a velocity of 5.0 m/s at an angle of 15 degrees with respect to the flat roof. If the other roof is 2.5 m below the building he jumps from, how far away can the other building be so he safely makes the jump?

Update:

Physics question 

4 Answers

Relevance
  • oubaas
    Lv 7
    2 months ago
    Favourite answer

    h-ho = Vo*sin 15°*t-g/2*t^2

    -2.5 = 5*0.259*t-4.9*t^2 

    -2.5-1.3t+4.9t^2 = 0

    t = (1.3+√ 1.3^2+2.5*4*4.9)/9.8 = 0.86 sec 

    d < Vo*t 

    d < 4.3 m 

  • NCS
    Lv 7
    2 months ago

    Use the trajectory equation so you don't need to find the time:

    y = h + x*tanΘ - gx² / (2v²cos²Θ)

    Dropping units for ease,

    0 = 2.5 + x*tan15º - 9.8x²/(2*5.0²cos²Θ) = 2.5 + 0.268x - 0.21x²

    quadratic with roots at x = -2.9 m ← ignore

    and x = 4.1 m ◄

    Attachment image
  • Anonymous
    2 months ago

    i just liked the movie                 

  • 2 months ago

    He will be hooked up to a wire harness, so the other building could theoretically be on the other side of town.

Still have questions? Get answers by asking now.