Anonymous
Anonymous asked in Education & ReferenceHomework Help · 1 month ago

Can I get help on my math homework?

The question is. Ashley is 10 years older than her sister Brianna. Two years ago, Ashley was 6 times Brianna’s age. How old is Brianna now? 

3 Answers

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  • 1 month ago

    Let the present age of :

    Brianna  =  x years.

    Ashley is 10 year older than Brianna.

    Hence present age of Ashley = x + 10 years.

    Two years ago : Brianna's age was = x - 2  years.

    And 2 yrs ago, Ashley's age was = Present age - 2 years  =  ( x + 10 ) - 2 = x + 8

    It is given that : Ashley was 6 times Brianna’s age.

    =>  x + 8 = 6 [ x - 2 ] 

    => 6 x - x  =  20

    => x = 4 yrs. ........ Present age of Brianna  .......... Answer

     

  • 1 month ago

    By 'Trial and Error 

    A = 14; B  = 4

    Two years ago 

    A = 12 & B = 2 

    2 x 6 = 12 

    Algebraically 

    A = B + 10 

    A - 2 = 6( B - 2) 

    A = B  + 10 

    A -2 = 6B - 12 

    Substitute 

    B + 10 - 2 = 6B - 12 

    B + 8 = 6B - 12

    5B = 20 

    B = 4  (Brianna age now)!!!!!  

  • Anonymous
    1 month ago

    Brianna is 4 

    lets ages now be A and B:       so A =  B + 10

    and two years ago: A - 2 = 6 (B - 2)   which makes  A  = 6B -10

    Substitute for A and solve

    6B  - 10 = B + 10   which gives 5B = 20, so B = 4

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