# Can I get help on my math homework?

The question is. Ashley is 10 years older than her sister Brianna. Two years ago, Ashley was 6 times Brianna’s age. How old is Brianna now?

### 3 Answers

- Pramod KumarLv 71 month ago
Let the present age of :

Brianna = x years.

Ashley is 10 year older than Brianna.

Hence present age of Ashley = x + 10 years.

Two years ago : Brianna's age was = x - 2 years.

And 2 yrs ago, Ashley's age was = Present age - 2 years = ( x + 10 ) - 2 = x + 8

It is given that : Ashley was 6 times Brianna’s age.

=> x + 8 = 6 [ x - 2 ]

=> 6 x - x = 20

=> x = 4 yrs. ........ Present age of Brianna .......... Answer

- lenpol7Lv 71 month ago
By 'Trial and Error

A = 14; B = 4

Two years ago

A = 12 & B = 2

2 x 6 = 12

Algebraically

A = B + 10

A - 2 = 6( B - 2)

A = B + 10

A -2 = 6B - 12

Substitute

B + 10 - 2 = 6B - 12

B + 8 = 6B - 12

5B = 20

B = 4 (Brianna age now)!!!!!

- Anonymous1 month ago
Brianna is 4

lets ages now be A and B: so A = B + 10

and two years ago: A - 2 = 6 (B - 2) which makes A = 6B -10

Substitute for A and solve

6B - 10 = B + 10 which gives 5B = 20, so B = 4