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341 L of a gas at 10oC are under 309 kPa of pressure. If the pressure is changed to 611 kPa and the temperature is decreased to -1oC, what volume will the gas occupy? (4 marks)

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- hcbiochemLv 72 months agoFavourite answer
Use the combined gas law:

P1V1/T1 = P2V2/T2

Remembering that your temperatures must be in Kelvin. So,

309 kPa (341 L)/ 283 K = 611 kPa (V2) / 272 K

V2 = 166 L

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