Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and, as of 20 April 2021 (Eastern Time), the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

brooke asked in Science & MathematicsPhysics · 2 months ago

# physics problem?

calculate the period of a pendulum that is 1.42 m long. What is this pendulum’s frequency?

period-

frequency-

### 3 Answers

Relevance
• oubaas
Lv 7
2 months ago
Favourite answer

period T = 2PI/√g * √L = 2.01*1.19 = 2.40 sec

frequency f = 1/T = 1/2.40 = 0.418 Hz

• NCS
Lv 7
2 months ago

For a simple pendulum,

period T = 2π√(L/g) = 2π√(1.42m / 9.81m/s²) = 2.39 s

frequency f = 1/T = 0.418 s⁻¹ = 0.418 Hz

• mg
Lv 7
2 months ago

Period:

T = 2 * 3,14 *square root(L / g);

T = (2 * 3,14)* square root(1,42/ 9,8) = 2,39 s;

f = 1/ T = 1 / 2,39 = 0,42 Hz. ( Frequency).

Ciao

Still have questions? Get answers by asking now.