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physics problem?

calculate the period of a pendulum that is 1.42 m long. What is this pendulum’s frequency?

period-

frequency- 

3 Answers

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  • oubaas
    Lv 7
    2 months ago
    Favourite answer

    period T = 2PI/√g * √L = 2.01*1.19 = 2.40 sec 

    frequency f = 1/T = 1/2.40 = 0.418 Hz 

  • NCS
    Lv 7
    2 months ago

    For a simple pendulum,

    period T = 2π√(L/g) = 2π√(1.42m / 9.81m/s²) = 2.39 s

    frequency f = 1/T = 0.418 s⁻¹ = 0.418 Hz

  • mg
    Lv 7
    2 months ago

    Period:

    T = 2 * 3,14 *square root(L / g);

    T = (2 * 3,14)* square root(1,42/ 9,8) = 2,39 s;

    f = 1/ T = 1 / 2,39 = 0,42 Hz. ( Frequency).

    Ciao

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