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calculate the period of a pendulum that is 1.42 m long. What is this pendulum’s frequency?
- oubaasLv 72 months agoFavourite answer
period T = 2PI/√g * √L = 2.01*1.19 = 2.40 sec
frequency f = 1/T = 1/2.40 = 0.418 Hz
- NCSLv 72 months ago
For a simple pendulum,
period T = 2π√(L/g) = 2π√(1.42m / 9.81m/s²) = 2.39 s
frequency f = 1/T = 0.418 s⁻¹ = 0.418 Hz
- mgLv 72 months ago
T = 2 * 3,14 *square root(L / g);
T = (2 * 3,14)* square root(1,42/ 9,8) = 2,39 s;
f = 1/ T = 1 / 2,39 = 0,42 Hz. ( Frequency).