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Anonymous

# can anyone help with Chem please? ?

How much heat is absorbed if a .122 g sample of water goes from 365 K to 367 K?

-1.02 J

+ 1.02 J

3.3 J

.055 J

How much heat is released when a 22 g sample of water cools from 32 C to 29 C?

+ 276 calories

- 2.8 x 10^2 joules

+ 8.4 x 10^-2 joules

- 3.3 x 10^1 joules

### 1 Answer

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- Roger the MoleLv 71 month agoFavourite answer
(4.184 J/g·°C) x (0.122 g) x (367 - 365)°C = +1.02 J

(4.184 J/g·°C) x (22 g) x (32 - 29)°C = -276 J = -2.8 x 10^2 J

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